In the figure below, QRST is a rhombus. QVS is a straight line.
∠TUV=46∘\angle TUV = 46^\circ and ∠RQV=20∘\angle RQV = 20^\circ
Find ∠QVU\angle QVU. Answer: ___ ∘^\circ

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Worked solution

25

1. Find $\angle UQV$ using the property of the diagonal of a rhombus.

In a rhombus, the diagonal bisects the interior angles. Since QVSQVS is the diagonal QSQS, we have:
∠UQV=∠TQS=∠RQS=20∘\angle UQV = \angle TQS = \angle RQS = 20^\circ

2. Find $\angle QVU$ using the exterior angle of a triangle.

For △QUV\triangle QUV, the exterior angle at UU is ∠TUV\angle TUV. Therefore:
∠TUV=∠UQV+∠QVU\angle TUV = \angle UQV + \angle QVU
46∘=20∘+∠QVU46^\circ = 20^\circ + \angle QVU
∠QVU=46∘−20∘=26∘\angle QVU = 46^\circ - 20^\circ = 26^\circ

Answer

2626

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