Roy made a model of his yacht with a scale of 1 : 40.

  1. (a)

    The actual length of the yacht is 12.5 m, find the length of the model in cm.

    Answer ...cm

  2. (b)

    Roy wants to spray paint his yacht. He can select either of the following options to paint his yacht.

    Option A: A lump sum payment of $1 000
    Option B: Payment for cost of paint at $5.50 per m^2
    [Cost of manpower is included in both options]

    If the total surface area of the model to be painted is 937.5 cm^2, find the surface area of his yacht. Which one of the two options should Roy select to paint his yacht? [Show your workings clearly]

    Answer ...

    ...

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Worked solution

10(a)

1. Convert the actual length to centimetres and apply the scale factor.

Scale 1:401:40 means
model length:actual length=1:40.\text{model length} : \text{actual length} = 1:40.
Actual length =12.5 m=1250 cm=12.5\text{ m}=1250\text{ cm}.
model length=125040=31.25 cm\text{model length}=\frac{1250}{40}=31.25\text{ cm}

Answer

31.25 cm31.25\text{ cm}

10(b)

1. Find the actual surface area using the area scale factor.

The scale of model : actual is 1:401:40.

Area scale factor from model to actual:
402=160040^2=1600

Actual surface area:
937.5×1600=1 500 000 cm2937.5\times1600=1\,500\,000\text{ cm}^2

2. Convert the actual surface area from square centimetres to square metres.

Since 1 m2=10 000 cm21\text{ m}^2=10\,000\text{ cm}^2,
1 500 000 cm2=1 500 00010 000=150 m21\,500\,000\text{ cm}^2=\frac{1\,500\,000}{10\,000}=150\text{ m}^2

3. Compare the two painting options and choose the cheaper option.

Option A costs $1000.

Option B costs:
150×5.50=825150\times5.50=825
So Option B costs $825.

Since $825 < \1000, Roy should select Option B.

Answer

Surface area of yacht =1500 m2=1500\text{ m}^2. Roy should select Option A.

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