A parallelogram ABCD is drawn on a square grid inside a box.

  1. (a)

    By joining dots on the grid with straight lines, draw square ADEF. Square ADEF must not overlap with parallelogram ABCD.

  2. (b)

    By joining dots on the grid with straight lines, draw trapezium CDGH such that CD is twice as long as GH, GH is parallel to CD and DG /\ CH. Trapezium CDGH must not overlap with parallelogram ABCD.

  3. (c)

    Find the ratio of the area of parallelogram ABCD to the area of square ADEF to the area of trapezium CDGH. Express your answer in its simplest form.

Work through it with AI →

It won't just hand you the answer — it asks where you're stuck.How the checker works

Worked solution

No solution to show yet.

Worked this one out on paper? Snap your steps and Gigle's AI math checker will circle the step where it went wrong.

More questions on this topic

  1. 1The normal to the curve y=2tan⁡3x−1y = 2\tan 3x - 1 at point P(π3,−1)P\left(\frac{\pi}{3}, -1\right) crosses the yy-axis at point AA…
  2. 2The point PP lies on the curve y=ln⁡(x+1x−1)y = \ln\left(\frac{x+1}{x-1}\right) for x>1x > 1. The normal to the curve at PP is par…
  3. 3The figure shows part of the curve y=g(x)y = g(x). (2,8)(2, 8) and (6,1)(6, 1) are two points on the curve. Given that ∫26y dx=32\int_{2}^{6} y \text{ } dx = 32…
  4. 4The diagram shows part of the curve y=3e−12x−6y = 3e^{-\frac{1}{2}x} - 6 which crosses the xx-axis at PP and the yy-axis at QQ…
  5. 5The triangle ABC is such that its area is 16+7102 cm2\dfrac{16 + 7\sqrt{10}}{2}\ \text{cm}^2, the length of AB is (32+5) cm(3\sqrt{2} + \sqrt{5})\ \text{cm}…