The scale of a map is 5 cm : 1 km. A reservoir has an actual area of 0.7 km^2. Find the area, in square centimetres, of the reservoir on the map. Answer ... cm^2 ABCD is a rhombus. X and Y are points on BD such that DX = YB. Show that triangle ADX is congruent to triangle ABY. Give a reason for each statement you make. Answer

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Worked solution

13(a)

1. Convert the linear map scale into an area scale.

Scale: 5 cm:1 km5\text{ cm} : 1\text{ km}

So,
1 km2 is represented by 52 cm2=25 cm2.1\text{ km}^2 \text{ is represented by } 5^2\text{ cm}^2 = 25\text{ cm}^2.

2. Find the map area corresponding to the actual area of $0.7\text{ km}^2$.

0.7 km2 is represented by 0.7×25=17.5 cm2.0.7\text{ km}^2 \text{ is represented by } 0.7 \times 25 = 17.5\text{ cm}^2.

Answer

17.5 cm217.5\text{ cm}^2

13(b)

1. State a pair of equal sides from the rhombus.

Since ABCDABCD is a rhombus,

AD=ABAD = AB

(all sides of a rhombus are equal).

2. State the given pair of equal segments on the diagonal.

Given that

DX=YB.DX = YB.

3. Show the included angles are equal.

Since ABCDABCD is a rhombus, opposite sides are parallel, so

AD∥BCandAB∥DC.AD \parallel BC \quad \text{and} \quad AB \parallel DC.

As XX and YY lie on BDBD, the angles ∠ADX\angle ADX and ∠ABY\angle ABY are the angles made by the same diagonal BDBD with the parallel sides ADAD and ABAB in the rhombus. Hence

∠ADX=∠ABY.\angle ADX = \angle ABY.

4. Conclude triangle congruence with a valid congruence test.

Therefore, in △ADX\triangle ADX and △ABY\triangle ABY,

AD=AB,DX=YB,∠ADX=∠ABY.AD = AB, \quad DX = YB, \quad \angle ADX = \angle ABY.

Hence

△ADX≅△ABY\triangle ADX \cong \triangle ABY

by SAS.

Answer

△ADX≅△ABY\triangle ADX \cong \triangle ABY by SAS.

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