On 6 June 2020, Elijah invested some money in a bank which pays a simple interest at a rate of 3.5% per annum. He received a total interest of $680.40 on 6 June 2023. Find the amount of money Elijah invested in the bank. Answer $... Freddy invested $8000 in another bank that paid compound interest at a rate of 1.75% per annum, compounded quarterly. Find the total amount Freddy received at the end of 5 years. Give your answer correct to the nearest cent. Answer $...

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Worked solution

5(a)

1. Find the time period of the investment in years and write the simple interest relation.

From 6 June 2020 to 6 June 2023, the time is 33 years.

For simple interest,
I=PrtI = Prt
where I=680.40I=680.40, r=3.5%=0.035r=3.5\%=0.035, and t=3t=3.

2. Rearrange and calculate the principal invested.

680.40=P(0.035)(3)680.40 = P(0.035)(3)
680.40=0.105P680.40 = 0.105P
P=680.400.105=6480P = \frac{680.40}{0.105}=6480

Answer

$6480

5(b)

1. Find the quarterly interest rate and the total number of compounding periods.

Since the interest is compounded quarterly,

quarterly rate=1.75%4=0.4375%\text{quarterly rate}=\frac{1.75\%}{4}=0.4375\%

Over 5 years,

number of quarters=5×4=20\text{number of quarters}=5\times 4=20

2. Apply the compound interest formula and round to the nearest cent.

A=8000(1+0.4375100)20A=8000\left(1+\frac{0.4375}{100}\right)^{20}

A=8000(1.004375)20A=8000(1.004375)^{20}

A=8729.871…A=8729.871\ldots

To the nearest cent,

A=8729.87A=8729.87

Answer

$8729.87

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