使用所有的数字 0, 4, 5, 9 来组成

  1. (a)

    是 5 的倍数的最大数。

    答:(a) ___

  2. (b)

    最接近 5000 的数。

    答:(b) ___

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完整解法

1(a)

1. Identify the condition for the number to be a multiple of 5

For a number to be a multiple of 55, its last digit must be 00 or 55.

2. Determine the largest possible arrangement of the remaining digits

To form the largest number, we must place the largest available digits in the highest place values.

  • If the last digit is 00, the remaining digits are 4,5,94, 5, 9. Arranging them in descending order gives 95409540.
  • If the last digit is 55, the remaining digits are 0,4,90, 4, 9. Arranging them in descending order gives 94059405.
    Comparing the two, 9540>94059540 > 9405.
答案

95409540

1(b)

1. Identify the largest possible number starting with 4 and the smallest possible number starting with 5

The number just below 50005000 must start with 44 and be as large as possible: 49504950.
The number just above 50005000 must start with 55 and be as small as possible: 50495049.

2. Calculate the difference between each candidate and 5000 to find the closest

Difference for 49504950: 5000−4950=505000 - 4950 = 50
Difference for 50495049: 5049−5000=495049 - 5000 = 49
Since 49<5049 < 50, 50495049 is closer to 50005000.

答案

50495049

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