The ratio of the number of stickers Kingston had to the number of stickers Tim had was 8 : 5. After Kingston gave away 44 stickers, Tim had twice as many stickers as Kingston. How many stickers did they have at first? Answer : ___

1. Identify the initial ratio and the unchanged quantity

Initial ratio of Kingston to Tim is $8 : 5$.
Tim's number of stickers remains unchanged.

2. Express the final ratio and make the unchanged quantity's units equal

Final ratio of Kingston to Tim is $1 : 2$.
To make Tim's units equal in both ratios, we find the LCM of $5$ and $2$, which is $10$.
Initial ratio (Kingston : Tim) = $16 : 10$
Final ratio (Kingston : Tim) = $5 : 10$

3. Find the value of 1 unit

Decrease in Kingston's units = $16 - 5 = 11$ units.
$11 \text{ units} = 44 \text{ stickers}$
$1 \text{ unit} = 44 \div 11 = 4 \text{ stickers}$

4. Calculate the total number of stickers at first

Total units at first = $16 + 10 = 26$ units.
Total stickers at first = $26 \times 4 = 104$