Tim had 23\frac{2}{3} as much money as Peter. After Tim received $120 from his mother and Peter used $120, Tim had twice as much money as Peter. How much money did Tim have at first? Ans: ___

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Worked solution

13

1. Identify that the total amount of money remains unchanged and set up the initial and final ratios.

Since Tim receives $120 and Peter uses $120, the total amount of money they have together remains constant.
Initial ratio of Tim to Peter = 2:32 : 3 (Total = 55 units)
Final ratio of Tim to Peter = 2:12 : 1 (Total = 33 units)

2. Make the total units the same for both ratios to compare them.

LCM of 55 and 33 is 1515.
Multiply the initial ratio by 33:
Initial Tim : Peter = 6:96 : 9 (Total = 1515 units)
Multiply the final ratio by 55:
Final Tim : Peter = 10:510 : 5 (Total = 1515 units)

3. Find the value of 1 unit and calculate Tim's initial money.

Increase in Tim's units = 10−6=410 - 6 = 4 units
4 units=$1204 \text{ units} = \char36{}120
1 unit=$120÷4=$301 \text{ unit} = \char36{}120 \div 4 = \char36{}30
Tim's initial money = 6 units=6×$30=$1806 \text{ units} = 6 \times \char36{}30 = \char36{}180

Answer

$180

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