Factorise completely 2x3−13x2+6x2x^3 - 13x^2 + 6x. Answer ...

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Worked solution

3

1. Extract the common factor from all terms.

2x3−13x2+6x=x(2x2−13x+6)2x^3-13x^2+6x=x(2x^2-13x+6)

2. Factorise the quadratic expression completely.

Find two factors of 2×6=122\times 6=12 that add to −13-13: −12-12 and −1-1.

2x2−13x+6=2x2−12x−x+62x^2-13x+6=2x^2-12x-x+6
=2x(x−6)−1(x−6)=2x(x-6)-1(x-6)
=(2x−1)(x−6)=(2x-1)(x-6)

Hence,
2x3−13x2+6x=x(2x−1)(x−6).2x^3-13x^2+6x=x(2x-1)(x-6).

Answer

x(2x−1)(x−6)x(2x-1)(x-6)

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