Both Farah and Jamil left their houses at the same time to go to the park. Farah travelled 20 km from her house to the park at an average speed of 30 km/h. Jamil travelled from his house at an average speed of 42 km/h and reached the park 15 minutes later than Farah. What was the distance between Jamil's home and the park? Ans: ___

1. Calculate the time taken by Farah to reach the park

Time taken by Farah $= \frac{\text{Distance}}{\text{Speed}} = \frac{20}{30} = \frac{2}{3}$ hours.
$\frac{2}{3}$ hours $= \frac{2}{3} \times 60 = 40$ minutes.

2. Calculate the time taken by Jamil

Since Jamil left at the same time but arrived 15 minutes later, his travel time is:
$40 + 15 = 55$ minutes.
Convert this back to hours: $\frac{55}{60} = \frac{11}{12}$ hours.

3. Calculate the distance Jamil travelled

Distance $= \text{Speed} \times \text{Time} = 42 \times \frac{11}{12} = \frac{42 \times 11}{12} = 38.5$ km.