In an experiment with 16 observations on x, the following results were obtained: ∑x=182\sum x = 182, ∑x2=3548\sum x^2 = 3548 One observation with value 20 was detected to be wrongly recorded and was replaced by its correct value 30. Find the corrected standard deviation.

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Worked solution

8

1. Correct the sum of the observations

The incorrect value 2020 is replaced by 3030.

∑x=182−20+30=192\sum x = 182 - 20 + 30 = 192

2. Correct the sum of squares of the observations

∑x2=3548−202+302\sum x^2 = 3548 - 20^2 + 30^2

=3548−400+900=4048= 3548 - 400 + 900 = 4048

3. Apply the standard deviation formula

There are n=16n=16 observations.

standard deviation=∑x2n−(∑xn)2\text{standard deviation}=\sqrt{\frac{\sum x^2}{n}-\left(\frac{\sum x}{n}\right)^2}

=404816−(19216)2=\sqrt{\frac{4048}{16}-\left(\frac{192}{16}\right)^2}

=253−122=\sqrt{253-12^2}

=109=10.4 correct to 3 significant figures=\sqrt{109}=10.4\text{ correct to 3 significant figures}

Answer

Corrected standard deviation =7.08= 7.08

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