Section B: Probability and Statistics [60 marks] The basketball club in a college has 5 centers, 8 forwards and 7 guards. With the National School Games approaching, the coach wishes to find out the opinions of members of the club about the training programme. He gives a questionnaire to all the members of the club and receives replies from everyone. The coach then decides to select teams to play in the matches for National School Games. A basketball team to play in a match consists of 1 center, 2 forwards and 2 guards.

  1. (a)

    Explain whether the 20 members form a sample or a population.

  2. (b)

    Explain an advantage for choosing a random sample in each category of members for the match.

  3. (c)

    How many different teams can be formed?

  4. (d)

    In the club, one particular forward is the classmate of one particular guard. Both classmates are injured and cannot participate in a particular match. The coach decides that one of the remaining guards can play either as a guard or as a forward.

    How many different teams can now be formed?

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Worked solution

5(a)

1. State whether the group is a population or a sample, and provide the justification based on the context.

The coach wants to find out the opinions of the "members of the club". The club has 5+8+7=205 + 8 + 7 = 20 members. Since the 20 members constitute the entire target group of interest for the survey, they form a population.

Answer

They form a population, as they include all the members of the basketball club which is the entire group the coach is interested in surveying.

5(b)

1. State the advantage of category-based (stratified) random sampling over simple random sampling for this specific context.

Choosing a random sample in each category ensures that the team formed will have the exact required composition of playing positions (1 center, 2 forwards, and 2 guards) for the match. A simple random sample of 5 members from the entire club might fail to produce a valid team composition.

Answer

Choosing a random sample in each category ensures that the team formed will have the exact required composition of playing positions (1 center, 2 forwards, and 2 guards) for the match. A simple random sample of 5 members from the entire club might fail to produce a valid team composition.

5(c)

1. Set up the product of combinations for each position

Number of teams=5C1×8C2×7C2\text{Number of teams} = {}^{5}C_1 \times {}^{8}C_2 \times {}^{7}C_2

2. Evaluate the combinations to find the total number of teams

=5×28×21=2940= 5 \times 28 \times 21 = 2940

Answer

29402940

5(d)

1. Identify the available players and their specific roles

After the 2 injuries, the available players are:

  • 55 Centers
  • 77 Forwards (strictly forwards)
  • 66 Guards, comprising 55 strictly Guards and 11 versatile player (who can play as a Forward or Guard).

2. Calculate the number of teams if the versatile player is NOT selected

Choose 11 Center from 55, 22 Forwards from 77, and 22 Guards from 55:
Ways=5C1×7C2×5C2=5×21×10=1050\text{Ways} = {^5C_1} \times {^7C_2} \times {^5C_2} = 5 \times 21 \times 10 = 1050

3. Calculate the number of teams if the versatile player is selected as a Forward

The versatile player fills 11 Forward spot. We need 11 Center from 55, 11 more Forward from 77, and 22 Guards from 55:
Ways=5C1×7C1×5C2=5×7×10=350\text{Ways} = {^5C_1} \times {^7C_1} \times {^5C_2} = 5 \times 7 \times 10 = 350

4. Calculate the number of teams if the versatile player is selected as a Guard, and find the overall total

The versatile player fills 11 Guard spot. We need 11 Center from 55, 22 Forwards from 77, and 11 more Guard from 55:
Ways=5C1×7C2×5C1=5×21×5=525\text{Ways} = {^5C_1} \times {^7C_2} \times {^5C_1} = 5 \times 21 \times 5 = 525

Total number of teams is the sum of these mutually exclusive cases:
Total=1050+350+525=1925\text{Total} = 1050 + 350 + 525 = 1925

Answer

1925

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