y=12−6x3y = 12 - 6x^{3}

  1. (a)

    Find yy when x=−1x = -1.

    Answer ___

  2. (b)

    Rearrange the formula to make xx the subject.

    Answer ___

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Worked solution

3(a)

1. Substitute $x=-1$ into the formula and evaluate $y$.

y=12−6(−1)3y=12-6(-1)^3
y=12−6(−1)y=12-6(-1)
y=12+6=18y=12+6=18

Answer

1818

3(b)

1. Isolate $x^3$ and then take the cube root to make $x$ the subject.

y=12−6x3y=12-6x^3
6x3=12−y6x^3=12-y
x3=12−y6x^3=\frac{12-y}{6}
x=12−y63x=\sqrt[3]{\frac{12-y}{6}}

Answer

x=12−y63x=\sqrt[3]{\dfrac{12-y}{6}}

AI analysis — may contain mistakes.

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