A packet of chocolates contains pieces of milk, dark and orange chocolates. 25% of the chocolates are dark chocolates. The ratio of the number of dark chocolates to the number of milk chocolates is 5 : 7. There are 78 pieces of dark and orange chocolates. What is the total number of pieces of chocolates in the packet?

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Worked solution

13

1. Find the percentage of milk chocolates using the given ratio

The ratio of dark to milk chocolates is 5:75 : 7. Since dark chocolates make up 25%25\% of the total, 5 units=25%5 \text{ units} = 25\%.
1 unit=25%÷5=5%1 \text{ unit} = 25\% \div 5 = 5\%.
Percentage of milk chocolates = 7×5%=35%7 \times 5\% = 35\%.

2. Find the percentage of orange chocolates

Percentage of orange chocolates = 100%−25%−35%=40%100\% - 25\% - 35\% = 40\%.

3. Find the total percentage of dark and orange chocolates

Percentage of dark and orange chocolates = 25%+40%=65%25\% + 40\% = 65\%.

4. Calculate the total number of chocolates

We are given that there are 7878 pieces of dark and orange chocolates.
65%→7865\% \rightarrow 78
1%→7865=1.21\% \rightarrow \frac{78}{65} = 1.2
100%→1.2×100=120100\% \rightarrow 1.2 \times 100 = 120
The total number of chocolates is 120120.

Answer

120120 (option 2)

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