The function is defined by , for , .
- (i)
Show that for . Hence, or otherwise, show that has an inverse.
- (ii)
Sketch on the same diagram the graphs of and .
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Worked solution
2(i)
1. Find the first derivative of $\text{g}(x)$.
2. Show that the derivative is strictly positive on the given open interval.
For , the range of is .
Since , it follows that .
Hence, for .
3. Deduce that the function has an inverse.
Since for the interior of its domain, is a strictly increasing function.
A strictly increasing function is a one-to-one function (it passes the horizontal line test).
Therefore, the inverse function exists.
Shown.
2(ii)
1. Identify key coordinates, relative position to $y=x$, and endpoint tangents of $y = \text{g}(x)$.
Since , the graph of has horizontal tangents at the endpoints and .
Furthermore, for , , so the curve lies above the line . Conversely, for , , meaning the curve lies below .
2. Deduce the corresponding properties for $y = \text{g}^{-1}(x)$ using the reflection property of inverse functions.
The graph of is the reflection of in the line .
Therefore, it will share the intersection points , , and .
The horizontal tangents of become vertical tangents for at the endpoints.
For , lies below , and for , it lies above .
3. Produce the combined sketch.
(Student draws the axes, sketching the line as a guide, and carefully draws and exhibiting the correct intersection points, relative positions, and tangent behaviors at the extremities.)
A sketch containing both curves on the interval . They intersect at , , and .
- has horizontal tangents at the endpoints and lies above for .
- has vertical tangents at the endpoints and lies below for .
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