A镇和B镇之间的距离是 1260 km。火车 X 于上午 8:00 从 A镇出发开往 B镇，平均速度为 230 km/h。与此同时，火车 Y 从 B镇出发开往 A镇，平均速度为 190 km/h。

  1. (a)

    它们在什么时间相遇？

    答案：(a) ___

  2. (b)

    当它们在途中相遇时，每辆火车各行驶了多远？

    1. (b(i))

      火车 X：___

    2. (b(ii))

      火车 Y：___

English
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完整解法

9(a)

1. Calculate the relative speed of the two trains

Relative speed = 230+190=420230 + 190 = 420 km/h

2. Calculate the time taken for the trains to meet

Time taken = 1260420=3\frac{1260}{420} = 3 hours

3. Determine the meeting time

Meeting time = 3 hours after 8.00 a.m. = 11.00 a.m.

答案

11.00 a.m.

9(b)(b(i))

1. Find the time taken for the two trains to meet

Relative speed=230+190=420 km/h\text{Relative speed} = 230 + 190 = 420\text{ km/h}
Time taken=1260420=3 hours\text{Time taken} = \frac{1260}{420} = 3\text{ hours}

2. Calculate the distance travelled by Train X

Distance=Speed×Time\text{Distance} = \text{Speed} \times \text{Time}
Distance=230×3=690 km\text{Distance} = 230 \times 3 = 690\text{ km}

答案

690 km690\text{ km}

9(b)(b(ii))

1. Determine the time taken for the trains to meet (from part a)

Relative speed=230+190=420 km/h\text{Relative speed} = 230 + 190 = 420\text{ km/h}
Time taken=1260420=3 hours\text{Time taken} = \frac{1260}{420} = 3\text{ hours}

2. Calculate the distance travelled by Train Y

Distance=Speed×Time=190×3=570 km\text{Distance} = \text{Speed} \times \text{Time} = 190 \times 3 = 570\text{ km}

答案

570 km570\text{ km}

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