杰森于下午 12:50 从 C 镇出发前往 D 镇。他以 60 km/h 的平均速度行驶。下午 1:30，彼得从 C 镇出发前往 D 镇，沿相同的路线以 90 km/h 的平均速度行驶。彼得在什么时间追上杰森？ 答案：下午 ___

1. Find the time difference between Jason's and Peter's departure

From $12.50\text{ p.m.}$ to $1.30\text{ p.m.}$ is $40\text{ minutes}$.
$40\text{ minutes} = \frac{40}{60}\text{ h} = \frac{2}{3}\text{ h}$

2. Calculate the distance Jason travelled before Peter started

$\text{Distance} = \text{Speed} \times \text{Time}$
$\text{Distance} = 60 \times \frac{2}{3} = 40\text{ km}$

3. Calculate the relative speed and time taken for Peter to catch up

$\text{Relative speed} = 90 - 60 = 30\text{ km/h}$
$\text{Time taken to catch up} = \frac{40}{30} = \frac{4}{3}\text{ h} = 1\text{ h } 20\text{ min}$

4. Determine the time Peter overtook Jason

$1.30\text{ p.m.} + 1\text{ h } 20\text{ min} = 2.50\text{ p.m.}$