两个连续正整数相乘。其积四舍五入到最接近的百位是 202100。求这两个正整数的和。 答案 ...

1. Set up an equation to estimate the value of the integers

Let the two consecutive positive integers be $n$ and $n+1$.
$n(n+1) \approx 202100$
$n^2 \approx 202100$
$n \approx \sqrt{202100} \approx 449.55$

2. Test integer values near the estimate to find the exact integers

Test $n = 449$:
$449 \times 450 = 202050$
When 202050 is rounded to the nearest hundred, it is 202100.
Thus, the two integers are 449 and 450.

3. Calculate the sum of the two integers

Sum $= 449 + 450 = 899$