在 08:00，帕特里克和约翰以恒定速度从 A 镇出发前往 B 镇。他们沿着相同的路线行驶。帕特里克的行驶速度比约翰快 25 km/h。当帕特里克到达 A 镇和 B 镇的中点时，约翰距离该中点还有 30 km。帕特里克在什么时间到达 B 镇？

1. Determine the time taken for Patrick to reach the mid-point

Difference in distance between Patrick and John at the mid-point = $30$ km.
Difference in speed = $25$ km/h.
Time taken to reach the mid-point = $\frac{30}{25} = 1.2$ hours.

2. Calculate the total time taken for Patrick to reach Town B

Total time taken = $1.2 \times 2 = 2.4$ hours.

3. Convert the total time into hours and minutes and find the arrival time

$2.4$ hours = $2$ hours and $24$ minutes.
Starting time = $08\ 00$.
Arrival time = $08\ 00 + 2$ h $24$ min = $10\ 24$.