起初，15 根路灯杆成一排等距离排列在 P 点到 Q 点之间。相邻 2 根路灯杆之间的距离是 26.6 m。然后，又增加了 5 根路灯杆。路灯杆在 P 点到 Q 点之间以新的等距离重新排列。求相邻两根路灯杆之间的新距离。

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完整解法

1. Find the number of intervals between the initial 15 lamp posts

Number of intervals initially = $15 - 1 = 14$

2. Calculate the total distance from point P to Q

Total distance = $14 \times 26.6 = 372.4$ m

3. Find the new total number of lamp posts and the new number of intervals

New number of lamp posts = $15 + 5 = 20$
New number of intervals = $20 - 1 = 19$

4. Calculate the new distance between two lamp posts

New distance = $372.4 \div 19 = 19.95$ m

答案

$19.95$ m

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